Question 189: Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
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Let Ronit's present age bexyears. Then, father's present age =(x+ 3x) years = 4xyears.(4x+ 8) =5(x+ 8)28x+ 16 = 5x+ 403x= 24x= 8.Hence, required ratio =(4x+ 16)=48= 2.(x+ 16)24