Question 163: From a point P on a level ground, the angle of elevation of the top tower is 30°. If the tower is 100 m high, the distance of point P from the foot of the tower is:
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Let AB be the tower.Then,APB = 30° and AB = 100 m.AB= tan 30° =1AP3AP= (AB x3) m= 1003m= (100 x 1.73) m= 173 m.