Question 221: In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?
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Total number of balls = (8 + 7 + 6) = 21.Let E= event that the ball drawn is neither red nor green= event that the ball drawn is blue.n(E) = 7.P(E) =n(E)=7=1.n(S)213