Question 216: It is being given that (232+ 1) is completely divisible by a whole number. Which of the following numbers is completely divisible by this number?
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Let 232=x. Then, (232+ 1) = (x+ 1).Let (x+ 1) be completely divisible by the natural number N. Then,(296+ 1) = [(232)3+ 1] = (x3+ 1) = (x+ 1)(x2-x+ 1), which is completely divisible by N, since (x+ 1) is divisible by N.