Question 212: The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is:
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Let original length =xmetres and original breadth =ymetres.Original area = (xy) m2.New length =120xm=6xm.1005New breadth =120ym=6ym.1005New Area =6xx6ym2=36xym2.5525The difference between the original area = xy and new-area 36/25 xy is= (36/25)xy - xy= xy(36/25 - 1)= xy(11/25) or (11/25)xyIncrease % =11xyx1x 100%= 44%.25xyVideo Explanation:https://youtu.be/I3jLjLPn1W4