What will be the output of the program?#include int main() { int y=128; const int x=y; printf("%d ", x); return 0; }

Question

Step 1:int y=128;The variable'y'is declared as an integer type and initialized to value "128".Step 2:const int x=y;The constant variable'x'is declared as an integer and it is initialized with the variable'y'value.Step 3:printf("%d
", x);It prints the value of variable'x'.Hence the output of the program is "128"

Accepted Answer

Answer

128

Answer

Garbage value

Answer

Error

Answer

0

Question 577: What will be the output of the program?#include<stdio.h> int main() { int y=128; const int x=y; printf("%d\n", x); return 0; }