What will be the output of the program?class BitShift
{
public static void main(String [] args)
{
int x = 0x80000000;
System.out.print(x + " and ");
x = x 31;
System.out.println(x);
}
}

Question

Option A is correct. The>>>operator moves all bits to the right, zero filling the left bits. The bit transformation looks like this:Before:1000 0000 0000 0000 0000 0000 0000 0000After:0000 0000 0000 0000 0000 0000 0000 0001Option C is incorrect because the>>>operator zero fills the left bits, which in this case changes the sign ofx, as shown.Option B is incorrect because the output methodprint()always displays integers in base 10.Option D is incorrect because this is the reverse order of the two output numbers.

Accepted Answer

Answer

-2147483648 and 1

Answer

0x80000000 and 0x00000001

Answer

-2147483648 and -1

Answer

1 and -2147483648

Question 735: What will be the output of the program?class BitShift { public static void main(String [] args) { int x = 0x80000000; System.out.print(x + " and "); x = x >>> 31; System.out.println(x); } }