What will be the output of the program?public class RTExcept
{
public static void throwit ()
{
System.out.print("throwit ");
throw new RuntimeException();
}
public static void main(String [] args)
{
try
{
System.out.print("hello ");
throwit();
}
catch (Exception re )
{
System.out.print("caught ");
}
finally
{
System.out.print("finally ");
}
System.out.println("after ");
}
}

Question

Themain()method properly catches and handles theRuntimeExceptionin the catch block, finally runs (as it always does), and then the code returns to normal.A, B and C are incorrect based on the program logic described above. Remember that properly handled exceptions do not cause the program to stop executing.

Accepted Answer

hello throwitRuntimeExceptioncaught after

Answer

hello throwit caught

Answer

Compilation fails

Answer

hello throwit caught finally after